Re: dynamic function definition

From:
"Maxim Yegorushkin" <maxim.yegorushkin@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
12 Jul 2006 18:14:51 -0400
Message-ID:
<1152683851.292122.302600@s13g2000cwa.googlegroups.com>
cesco wrote:

Hi,

I need to define the body of a function in the constructor of a class.
For example, the class has a member function Log (that is the public
interface of the class), but I want the body of this function to be
defined as something or as something else in the constructor of the
class:

class MyClass
{
public:
    void Log(const int& id, const int& value);
private:
    void LogON(const int& id, const int& value);
    void LogOFF();

};

MyClass::MyClass
{
    // define here whether the function "Log" will behave as LogON or
LogOFF according to a switch
}

void MyClass::LogON(const int& id, const int& value)
{
    // do something like push_back
}

void MyClass::LogOFF()
{
    // do nothing
}

// don't know if I need or not the following definition
void MyClass::Log(const int& id, const int& value)
{
}

Any suggestion on how to do this?


You could use an indirect call. IOW, Log function would call another
member function (LogON/OFF) through a (member) function pointer set in
the constructor.

Another option would be for a caller to check whether the class accepts
logging and call the member function if so. An if check is often faster
than a call and it is common when they wrap the check in a macro like
the following:

#define LOG_DETAIL_DO_LOG(lg, lvl, msg...) \
    do { if((lg).does_accept(logging::lvl)) (lg).write(__LINE__, msg);
} while(0)
#define LOG_DBG(lg, msg...) LOG_DETAIL_DO_LOG(lg, log_dbg, msg)

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