Re: Difference in compilation success with friend declaration
John Moeller schrieb:
If not, would I have to declare C public? Or is there
some other way to declare the friend that would work?
Regarding a current workaround I propose the
following replacement of your implementation:
Note that I introduced a publicly accessable
class CP which has a interface that can only
be used by the dedicated do_foo<CP>() function
similarily to your original question. If you
accept this change, you could even save class
CP and make C similarily publicly available.
//---------------------------------------
#include <iostream>
#include <ostream>
template <typename X>
void do_foo() {}
template <typename X>
struct A {
void foo() {
do_foo<X>();
}
};
struct CP;
class B {
struct C {};
friend class CP;
public:
A<CP> a;
};
class CP {
B::C data;
enum Janitor { Ticket };
friend void do_foo<CP>();
public:
static void foo(Janitor) {
std::cout << "Different output...\n";
}
};
template<>
void do_foo<CP>()
{
CP::foo(CP::Ticket);
}
int main()
{
B().a.foo();
}
//---------------------------------------
Greetings from Bremen,
Daniel Kr|gler
--
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