Re: C/C++ question on char*

From:
Pete Becker <pete@versatilecoding.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 01 Jun 2007 13:03:22 -0400
Message-ID:
<tKOdncgsUOHGzP3bnZ2dnUVZ_gOdnZ2d@giganews.com>
Peithon wrote:

int strspcmp(const char * s1, const char * s2)
{

    char* pS1 = s1;
    char* pS2 = s2;
    ...
    ...

}

As you can see, I assign the two const ptrs to some non-const ptrs to
do some ptr arithmetic,


I see something rather different. <g> s1 is a pointer to const char. pS1
is a pointer to (non-const) char. So *s1 = 'a'; isn't legal, but *pS1 =
'a'; is. That's why the compiler is warning you: the interface to
strspcmp says that it won't modify the passed strings, but the code
permits modification.

You can do pointer arithmetic on s1 and s2. They're not const.

Keep in mind that when you're using pointers you really have two
objects: the pointer and the thing it points to. Either or both of those
objects can be const. const char* is a non-const pointer to const char.
char*const is a const pointer to non-const char.

--

    -- Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com)
Author of "The Standard C++ Library Extensions: a Tutorial and
Reference." (www.petebecker.com/tr1book)

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