Re: const MyClass& operator= ... ...

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 10 Jul 2008 05:22:59 -0700 (PDT)
Message-ID:
<c3fc88a4-d3cb-4799-a677-eebfc93d3fb6@w7g2000hsa.googlegroups.com>
On Jul 9, 7:21 pm, Juha Nieminen <nos...@thanks.invalid> wrote:

Victor Bazarov wrote:

nembo kid wrote:

Was wondering why the function that overloads = operator,
returns always a const reference to the class.

Why the qualifier 'const'?


First of all, the premise is untrue. The compiler-provided
operator= does not return the reference to a const object.
It returns a reference to a non-const object.

Second, if one of _your_ classes returns a reference to
const, they you need to ask yourself (or whoever gave you
the class) why the normal (idiomatic) interface was not
followed.


In fact, the operator=() can return *anything* (including
void). However, if you return anything else than a reference
to self, your class cannot be used in the traditional way with
assignments (except with a simple "a = b;").


That's not quite true. A const reference return type will
support all of the traditionan C uses of assignment. (In C,
assignment was not an lvalue.) Where it breaks are things like:

    T&
    someFunction( /* ... */ )
    {
        // ...
        return a = b ;
    }

Arguably, such idioms aren't good programming practice, and
should be avoided anyway. But they work with built-in types and
with the compiler generated default operator, and it seems best
that user defined operators adher as close as possible to the
way the built-in operators work.

One notable exception to this is proxy objects, where the
operator= itself is usually const.

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