Re: a problem about "sqrt"

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 1 Nov 2008 02:06:46 -0700 (PDT)
Message-ID:
<2b6624a4-e40a-4fff-98a6-eeefe790c09a@s9g2000prm.googlegroups.com>
On Nov 1, 2:23 am, linlinfan...@163.com wrote:

why it print wrong result? I can't find the wrong place.

#include<stdio.h>
#include<math.h>

double distance(double a ,double b,double c,double d);

int main()
{
   double x1,y1,x2,y2;
   double result;

   printf("Enter four numbers:");
   scanf("%f%f%f%f",&x1,&y1,&x2,&y2);

   result=distance(x1,y1,x2,y2);

   printf("The distancd is %.1f",result);

   return 0;
}

double distance(double a,double b,double c,double d)
{
   return sqrt((a-c)*(a-c)+(b-d)*(b-d));
}


The reason why it prints the wrong result is that you're using
scanf. Try doing it the C++ way:

    #include <iostream>
    #include <cstddef>
    #include <cmath>

    extern double distance( double a, double b, double c, double d ) ;

    int
    main()
    {
        std::cout << "Please enter four numbers: " ;
        double x1 ;
        double y1 ;
        double x2 ;
        double y2 ;
        if ( std::cin >> x1 >> y1 >> x2 >> y2 ) {
            std::cout << "The distance is: "
                      << distance( x1, y1, x2, y2 )
                      << std::endl ;
        } else {
            std::cerr << "Those weren't four legal numbers"
                      << std::endl ;
        }
        return EXIT_SUCCESS ;
    }

    double
    distance(
        double x1,
        double y1,
        double x2,
        double y2 )
    {
        return std::sqrt( ((x1-x2) * (x1-x2)) + ((y1-y2)*(y1-y2)) ) ;
    }

You should just forget about stdio.h (except for a few things
like remove or rename); the interface is horribly broken, and
extremely error prone and unnatural. (The iostream interface
isn't without problems either, but it's still an order of
magnitude better than stdio.h.)

--
James Kanze (GABI Software) email:james.kanze@gmail.com
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