Re: C++ boxing

From:
peter koch larsen <peter.koch.larsen@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sat, 13 Feb 2010 17:21:57 CST
Message-ID:
<56563d26-4608-4d69-854c-73e95e15c26c@y33g2000yqb.googlegroups.com>
On 12 Feb., 23:43, pfultz2 <pful...@yahoo.com> wrote:

Is there a way to box a type in c++ like this:

class Interface
{
public:
    virtual void foo() = 0;

};

class A
{
public:
    void foo();

};

And then I could box this type like this:
Interface * a = box_cast<Interface*>(new A());

perhaps,
class B : public A, public virtual Interface
{

};

Maybe this is called something else in C++, because everytime i google
c++ boxing it refers me to .Net boxing, which is a similiar since a
struct in c# that has an interface isnt polymorphic, so it boxes the
type, essentially creating a new type that inherits that interface. Is
there a way to do something similiar in standard c++?


Why do you need this? For what you have told it looks like you don't
need anything at all.

Interface* i = new A;

is perfectly valid C++ code.

/Peter

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