Re: Can I use overloading for optional parameters?

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Tue, 30 Mar 2010 11:30:25 CST
Message-ID:
<d62ef430-3114-4b20-be72-43fb3884458a@j21g2000yqh.googlegroups.com>
On 30 Mrz., 17:49, DeMarcus <use_my_alias_h...@hotmail.com> wrote:

I need to provide a set of parameters to a function where one or more
can be optional. Standard C++ can only provide default values for the
last parameters and a default value representing N/A for references is
not quite pleasant.

I came up with an idea of overloading the optional parameters. Please
give me your feedback.

class SomeClass
{
public:

    void fnc( int& a );
    void fnc( int& a, int& b );
    void fnc( int& a, int& b, int& c );

    // Now insert a pointer if we want to disable (b).
    void fnc( int& a, int* b, int& c );
};


Do you mean "Now insert a **NULL** pointer if we want to disable"?
If not this interface would be quite misleading. Why should a pointer
to a valid int not be accepted?

int main()
{
    SomeClass sc;
    int a, b, c;

    // Just want to provide (a).
    sc.fnc( a );

    // Just want to provide (a) and (b).
    sc.fnc( a, b );

    // Just want to provide (a) and (c) but not (b).
    // Tricky to get right normally, but with this overloading
    // it works!
    sc.fnc( a, NULL, c );
}

Is this way to provide optional parameters ok, or will I bump into
trouble later I haven't foreseen here?


I cannot answer this question, because the answer depends on
the evolution of your parameters and the question, which
parameter combinations make sense.

My next question is; is there a way to use some technique like traits or
similar to make sure at compile time that (b) for sure is NULL?


Maybe a recent article of Alf

http://groups.google.de/group/comp.lang.c++.moderated/msg/178d5c2061d010f8

gives you an alternative approach?

HTH & Greetings from Bremen,

Daniel Kr?gler

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