Re: Comparing if two objects are of same type without RTTI

From:
Juha Nieminen <nospam@thanks.invalid>
Newsgroups:
comp.lang.c++
Date:
21 Apr 2011 08:55:38 GMT
Message-ID:
<4daff10a$0$2810$7b1e8fa0@news.nbl.fi>
vj <mr.vaibhavjain@gmail.com> wrote:

This makes it possible to check if two objects are of same type or not
even if RTTI support is not available (like we have on some embedded
platforms). I do understand that this method is only applicable if the
said classes have a vtable. But I am not sure if there are any other
gotchas' that I am overlooking. Whats your take on this.


  Besides being horribly non-portable (which should go without saying),
it doesn't work in cases of multiple inheritance, even if you limit
yourself to just using "interfaces" like in many other OO languages
(which means that nobody should have any rational or philosophical
objections to MI in this case).

  If C inherits from both A and B, comparing the (assumed) vptr at
the beginning of an object of type C with an object of type B will
obviously not produce the same result. In fact, most probably it
will not work when comparing objects of type C and A either. A dynamic
cast will, however, work properly in this situation.

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