Re: Question regarding cast

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 20 Jun 2013 06:32:42 -0700 (PDT)
Message-ID:
<4484c72a-2d3c-4bb8-9cab-bd690bd1f0dc@googlegroups.com>
On Thursday, 20 June 2013 04:22:00 UTC+1, Nobody wrote:

On Wed, 19 Jun 2013 23:05:21 +0000, Jorgen Grahn wrote:

As I understand this thread, none of this is a problem unless you override
the type system using reinterpret_cast<T> or something even worse. And
few people ever have to do that, to types like these, anyway.


This is an issue for interfacing C++ code to C, or to other languages
which have mechanisms for interfacing with C.


Since C doesn't have derived classes, I don't see how this can
be an issue. Classes which can be exported to C can't be
derived classes.

Consider:

    class SomeClass {...};

    // C API
    extern "C" {
    void *new_object() { return static_cast<void*>(new SomeClass()); }
    void free_object(void *obj) { delete static_cast<SomeClass*>(obj); }
    void object_foo(void *obj) { static_cast<SomeClass*>(obj)->foo(); }
    void object_bar(void *obj) { static_cast<SomeClass*>(obj)->bar(); }
    // ... and so on

    }

If you try to export the "an instance of a derived class is also an
instance of a base class" semantics to C, you'll get bitten by multiple
inheritance. You have to convert to the appropriate base class before
passing the pointer off to C code.


Obviously.

IMO it's a parallel to the endless
endianness/padding/alignment etc discussions. You can spend
a lifetime fighting that stuff ... but it's a non-issue
unless you break the type system. Willingly and on purpose.


Again, this can be necessary if you have to interface to the outside
world, particularly if efficiency is a consideration.


Again, it's not an issue *if* you respect the type system. One
of the rules of the types system is that to use a pointer
converted to void*, you have to convert it back to its original
type. Anything else is undefined behavior.

--
James

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