Re: Operator New help

From:
"john" <worldsoutro@gmail.com>
Newsgroups:
comp.lang.c++
Date:
29 Mar 2007 17:32:25 -0700
Message-ID:
<1175214745.790019.150460@d57g2000hsg.googlegroups.com>
On Mar 29, 4:12 pm, Gianni Mariani <gi3nos...@mariani.ws> wrote:

the code in the OP has a number of inconsistantcies.

john wrote:

Hey guys,

Quick question i have this code and what i want to do is create a deep
copy of class B. Now I tried doing this with the new operator and
pointers. Here's is the orignal

---------------- Original Copy-----------------------

#include <iostream>
using namespace std;

class A
{
  int n ;
  public:
   A():n(0)


The line above is valid - this is better:

A():n()

   {
   }
   A(int x):n(x)
   {
    n = x;


why make an assignment to what you already initialized it to ?

   }

   void print()
   { cout << n<<"\n\n";
   }


Why provide your own copy constructor ? Is not the one provided by the
compiler good enough here ?

    A(const A& objectCopy){

            n = objectCopy.n; // copy constructor

    }

   };

   class B
   {
    A * a;

     public:

    B(A & x)
      {
      a = &x; // Here is the problem so I implemented a new
command

        }

      void print ()
       {
         a->print();
         }
       B(const B& copy){ // Class B copy constructor
          a = copy.a;


the line above does not make a copy of the object.

         }
         const B &operator=(const B x){
          a = x.a; // Operator
         }
         B::~B(){
             delete a;


if you delete - make sure you have a correspoinding new.

                }
        };

      int main()
      {

        A a(5);
        A a1(7);

        a1.print();

        B b(a1);
        b.print();
         B c(a);
         b.print();
         b = c;

        b.print();
        cout << endl;
        int trick;
        cin >> trick;
        return 0;
        }

 //--------------------End of Orignal Copy-----------------------

----Version altered with new command in class B--------

#include <iostream>
using namespace std;

class A
{


... see earlier commens

   };

   class B
   {
    A * a;

     public:

    B(A & x)


B( const A & x )

      {
      a = new A(x); //New command


better

        }

      void print ()
       {
         a->print();
         }
       B(const B& copy){ // Class B copy constructor
          a = copy.a;


// try this one
B(const B& copy) a( new A(* copy.a) ){}

         }
         const B &operator=(const B x){
          a = x.a; // Operator


                delete a;
                a = new A(* copy.a);

         }
         B::~B(){
             delete a;

                }
        };

      int main()
      {

        A a(5);
        A a1(7);

        a1.print();

        B b(a1);
        b.print();
         B c(a);
         b.print();
         b = c;

        b.print();
        cout << endl;
        int trick;
        cin >> trick;
        return 0;
        }

 //---------------------------------------------------------------------
Works fine but say if i change main() so it looks like this

------------------ Aletered main -----------------

int main()
      {

        A a(5);

        B b = a;

        {

            A a1 (7);
            B b1 =a1;
            b = b1;
        }

        b.print();
        cout << endl;
        int trick;
        cin >> trick;
        return 0;
        }

--------------------- End of altered main--------------------

I get a bunch of junk so I found out i need to make a deep copy of B.


That's expected....
...

any help would be appreciated.


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hey Gianni,

 This code was given to me as trying to understand classes better. I
looked in the book and tried to make a new pointer to *a but falied
several times before I posted this message.

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