regex doesn't recognize a pattern in a string

From:
 hogcia <hogcia@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 07 Nov 2007 01:54:08 -0800
Message-ID:
<1194429248.324684.115540@57g2000hsv.googlegroups.com>
Hello!
I've got a little problem - I'm writing a program in C++, which should
compare a text input from keyboard with a regular expression and
return what parttern was recognized and where. The problem is the
program doesn't find a pattern even if it actually is in the string.
This is the code:

#include <regex.h>
#include <iostream>
#include <string>

using namespace std;

int main()
{
   regex_t preg;
   string s;
   string pattern = "\\(Name is [a-zA-Z]+\\)"; // "\\1" na koncu
wyrazenia
oznacza=B3oby dopasowanie jeszcze raz tego, co znajdzie do wyrazenia w
nawiasach
   int rc;
   size_t nmatch = 2;
   regmatch_t pmatch[2];

   cout << "Podaj string, w ktorym bedzie wyszukany wzorzec\n";

   getline(cin, s); //wczytuje do konca linii - w przeciwienstwie do
cin >>,
ktore wczytuje do spacji
   cout << s << endl;

   if(0 != (rc = regcomp(&preg, pattern.c_str(), REG_EXTENDED)))
   {
       printf("regcomp: Nie udalo sie skompilowac wyrazenia.");
       exit(EXIT_FAILURE);
   }

   if(0 != (rc = regexec(&preg, s.c_str(), nmatch, pmatch, 0)) ) //
funkcja
c_str zamienia typ string na const char *
   {
       printf("regexec: Nie udalo sie dopasowac stringu %s do
wyrazenia %s, rc =
%d\n", s.c_str(), pattern.c_str(), rc);
   }
   else
   {
       printf("W ca=B3ym wyra=BFeniu dopasowano wzorzec: \"%.*s\" na
pozycji od %d do
%d\n", pmatch[0].rm_eo-pmatch[0].rm_so, &s[pmatch[0].rm_so],
                            pmatch[0].rm_so, pmatch[0].rm_eo - 1);
   }

   regfree(&preg);

   return 0;
}

Any suggestions?

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