Re: How can you quickly find the number of elements stored in a a) static array b) dynamic array ?

From:
jkherciueh@gmx.net
Newsgroups:
comp.lang.c++
Date:
Sat, 12 Jan 2008 13:24:17 -0500
Message-ID:
<fmb0lc$42i$1@aioe.org>
James Kanze wrote:

On Jan 12, 3:27 pm, jkherci...@gmx.net wrote:

C C++ C++ wrote:

Hi all, got this interview question please respond.

How can you quickly find the number of elements stored in a
a) static array b) dynamic array ?


It would help if they said what they meant by dynamic array.
std::vector<>?

You do not mention, how the static array and the dynamic array
are given to you. Therefore, I will make some assumptions.

For an array of fixed size, you can use templates:

  template < typename T, unsigned long N >
  unsigned long length ( T const (&) [N] ) {


Wouldn't size_t be more appropriate as the return type. (It
could matter in the future, when size_t might be an unsigned
long long.)


Yes, std::size_t would be better.

 

    return ( N );


And of course, the paretheses aren't necessary here.


Not necessary, but I prefer them. I also write

  delete ( ptr );

knowing that the parentheses are not necessary. However, I do not want to
get into yet another futile discussion on style and taste; so I will not
provide any rationale for my preference.

  }

  #include <iostream>

  int main ( void ) {
    char arr [20];
    std::cout << length( arr ) << '\n';
  }

On the other hand, there shouldn't be a need for this: you
really want to avoid magic numbers like 20. Thus, you would
simply write the code like so:

  static const unsigned int my_array_size = 20;

  int main ( void ) {
    char arr [ my_array_size ];
    std::cout << my_array_size << '\n';
  }


Most of the time, I find it used when you have an initialized
array, with the size determined by the number of initializers.

There are a few cases where I'll go ahead with magic numbers, as
well. If the number is well known, and will never change: I'll
write 12 for the number of months in a year, rather than
defining an explicit constant, for example. But then, of
course, you know the size.

For an array of T dynamically allocated with new[] and stored
in a variable of type T*, you are simply out of luck:


But is there ever, ever a use for such a thing. I've been
programming in C++ for over 15 years now, and I've never used
array new.


I did: many of my classes are container-like. Ok, strictly speaking, I also
never new[] an array since the classes are all templated on an allocator.

although the compiler has to keep track of the array size (at
least if T has a non-trivial destructor and there is a
corresponding delete[]), there is no way in standard C++ to
get at that piece of information. Thus, you need to store the
length manually. If T is copy-constructible and assignable,
you should of course use std::vector instead. That will keep
track of the size for you.


And if T isn't copy-constructible and assignable, you're stuck
with an array with all of the elements initialized with the
default constructor, and no way to change the value, if you use
new[]. That doesn't sound very useful either.


Well, it could be a type that implements only one of the two concepts. (Not
that I know why one would do that:-)

Note: It is possible that one could use some trickery with a
user defined new-handler or some such thing, but I don't know
off hand how to do it and I doubt that it would be a good idea
anyway.


And it certainly wouldn't be a "quick way":-).


True.

Best

Kai-Uwe Bux

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