Re: accessing parent class method

From:

=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>

Newsgroups:

comp.lang.c++

Date:

Sun, 01 Jun 2008 07:57:59 GMT

Message-ID:

<bEs0k.7840$R_4.6462@newsb.telia.net>

On 2008-06-01 03:07, Victor Bazarov wrote:

ArbolOne wrote:

In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?

Post your code. It is easier when there is substance to the discussion.

Meanwhile, here is the example:

   struct foo {
       void foobar();
   };

   struct bar : foo {
       void foobar();
   };

   int main() {
       bar b;
       b.foobar(); // calls bar::foobar
       b.foo::foobar(); // call foo::foobar
   }

I would call it bad style to explicitly call a parent's implemenetation
of a function (and bad design if you have to), unless it is done in the
child's implementation of the same function:

#include<iostream>

struct foo1 {
  virtual void foobar() {
    std::cout << "foo1\n";
  }
};

struct foo2 : public foo1 {
  virtual void foobar() {
    std::cout << "foo2\n";
    foo1::foobar(); // Call foo1's foobar()
  }
};

int main() {
  foo1* f = new foo1();
  f->foobar();
  delete f;
  f = new foo2();
  f->foobar();
}

--
Erik Wikstr??m