Re: accessing parent class method
On Jun 1, 3:57 am, Erik Wikstr=F6m <Erik-wikst...@telia.com> wrote:
On 2008-06-01 03:07, Victor Bazarov wrote:
ArbolOne wrote:
In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?
Post your code. It is easier when there is substance to the discussion.=
Meanwhile, here is the example:
struct foo {
void foobar();
};
struct bar : foo {
void foobar();
};
int main() {
bar b;
b.foobar(); // calls bar::foobar
b.foo::foobar(); // call foo::foobar
}
I would call it bad style to explicitly call a parent's implemenetation
of a function (and bad design if you have to), unless it is done in the
child's implementation of the same function:
#include<iostream>
struct foo1 {
virtual void foobar() {
std::cout << "foo1\n";
}
};
struct foo2 : public foo1 {
virtual void foobar() {
std::cout << "foo2\n";
foo1::foobar(); // Call foo1's foobar()
}
};
int main() {
foo1* f = new foo1();
f->foobar();
delete f;
f = new foo2();
f->foobar();
}
--
Erik Wikstr=F6m
I got it now!
Thanks.
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