Type treated as an expression ???

From:
=?Utf-8?B?Um9iYnk=?= <Robby@discussions.microsoft.com>
Newsgroups:
microsoft.public.vc.language
Date:
Sat, 18 Jul 2009 20:40:00 -0700
Message-ID:
<A7ED7713-1481-498F-916F-CF40F3EF0722@microsoft.com>
Hello,

I am trying some sample code and I don't know why I am getting the
following error on the code below:

===================================
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct tag_xxx
{
long h[10];
}abc;

typedef struct tag_lb_table
{
long lb_items[5];
}lb_table;

int main()
{
abc *tx;

tx = malloc (sizeof (struct tag_xxx));
free(tx);

lb_table lb_dct1arr[] = { //<<< error points here!!!!
{ 0, 0, 0, 0, 0},
{ 181, 182, 183, 184, 0},
{ 185, 184, 183, 0, 0},
};

return 0;
}
=====================================

error:

1>c:\_dts_programming\c_programming\c\c_tests\c_string_samples\misc_c_samples\varraysasmembers.c(31)
: error C2275: 'lb_table' : illegal use of this type as an expression

lb_table is a type and I don't think I am using it as an expression ...

All help appreciated!

--
Best regards
Roberto

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