Re: Type treated as an expression ???
Thanks Igor!
Igor, I am stuck with a C coding dilema because of something I didn't think
of.
I will try to solve it ... hopefully I can get it to work... if not I will
post it.
Hope you will be around!
--
Best regards
Roberto
"Igor Tandetnik" wrote:
Robby wrote:
int main()
{
abc *tx;
tx = malloc (sizeof (struct tag_xxx));
free(tx);
lb_table lb_dct1arr[] = { //<<< error points here!!!!
{ 0, 0, 0, 0, 0},
{ 181, 182, 183, 184, 0},
{ 185, 184, 183, 0, 0},
};
return 0;
}
=====================================
error:
1>c:\_dts_programming\c_programming\c\c_tests\c_string_samples\misc_c_samples\varraysasmembers.c(31)
error C2275: 'lb_table' : illegal use of this type as an expression
In C, all variables must be declared at the top of the block, before the
first statement.
--
With best wishes,
Igor Tandetnik
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