Re: Dangling Pointer issue

From:
"Alf P. Steinbach /Usenet" <alf.p.steinbach+usenet@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 14 Apr 2011 19:32:32 +0200
Message-ID:
<io7b3g$nkf$1@dont-email.me>
* sg, on 14.04.2011 19:21:

In the below code

when we are passing by value in the function
SomeFunc(CDanglingPointers x) why the local object is not created?

class CDanglingPointers
{
public:
int *ptr;
CDanglingPointers(int i)
{
ptr = new int(i);
}

~CDanglingPointers()
{
delete ptr;
}
void PrintVal()
{
cout<< "The value is "<< *ptr;
}
};

void SomeFunc(CDanglingPointers x) => when we are passing by value why
the local object is not created?
{
cout<< "Say i am in someFunc "<< endl;
}

int main()
{
CDanglingPointers s1 = 10;
SomeFunc(s1);
s1.PrintVal();
}


First, please indent your code systematically.

Now, this looks like homework, so I'm not going to a detailed answer.

Rather, I'll just you pointers that you can use to get a grip on these things.

Main pointer: the code is in violation of the "rule of three" (google it), and
has Undefined Behavior.

When you pass the object by value, its copy constructor is invoked to copy the
object. Since you have not defined a copy constructor, the default automatically
generated one is used. And that one violates the "rule of three".

Cheers & hth.,

- Alf

--
blog at <url: http://alfps.wordpress.com>

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