Re: noob question - destructors - freeing memory...

From:
Garrett Hartshaw <ghartshaw@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 30 Dec 2011 22:50:29 -0500
Message-ID:
<almarsoft.4936771177436159932@news.eternal-september.org>
On Sat, 31 Dec 2011 02:43:28 +0100, someone <newsboost@gmail.com>
wrote:

Hi

See this (stolen from the internet):

----------------------------------------
#include <iostream>
using namespace std;

class Base
{
public:
   Base(){ cout<<"Constructing Base"<<endl;}

   // this is a destructor:
   virtual ~Base(){ cout<<"Destroying Base"<<endl;}
};

class Derive: public Base
{
public:
   Derive(){ cout<<"Constructing Derive"<<endl;}
   ~Derive(){ cout<<"Destroying Derive"<<endl;}
};

int main()
{
   Base *basePtr = new Derive();
   // delete basePtr; // <<<======== !! ! ! ! ! NB !!
   return 0;
}

----------------------------------------

See middle line of main():

   delete basePtr; // <<<======== !! ! ! ! ! NB !!

If I enable (uncomment) middle line, I get:
Constructing Base
Constructing Derive
Destroying Derive
Destroying Base

If I disable (comment out) middle line, I get:
Constructing Base
Constructing Derive

========

This, I didn't quite expect, because I thought that at the end of

the

program, all destructors where guaranteed to be called...

In my case, I have a longer program and I allocate memory with one

of my

constructors, hence it is crucial to free the memory, but since the
virtual destructor is never called, I never free the memory...

In addition: In my full program (not shown here), I instantiate my

new

object like:

int main(...)
{
   ...
   Derive d1();
   return 0; // or exit(1); if something went wrong somewhere
}

Is it required that I do, like in the example above:

int main(...)
{
   ...
   Base *myPtr = new Derive();
   delete myPtr;
   return 0; // or exit(1); if something went wrong somewhere
}

???????

But what if my code does an exit(1) somewhere, which it could do at
least a dozens of times, in different parts of the program?

Please advice, thank you!


A statically constructed object will be destroyed when the scope is
left.

e.g destructors will be called in:
int main()
{
   Derived d;
   return 0;
}

A dynamically constructed object (created using new) is destroyed
when delete is called.

e.g destructors called in this:
int main()
{
   Base * b = new Derived();
   delete b;
   return 0;
}

but not this:
int main()
{
   Base * b = new Derived();
   return 0;
}

When exit(int) is called, the program is terminated *without
unwinding the stack* so no destructors are called.

When a execption is thrown and not caught, the program is terminated
*with stack unwinding*, so static objects are destroyed.

Note:
int main()
{
   Base * b = new Derived();
   throw std::exception();
   delete b;
   return 0;
}

In the above, the delete expression is never reached, so destructors
are not called.
If this is an issue, a smart pointer (boost::shared_ptr,
boost::scoped_ptr, etc:) should be used.

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