Re: Function that reproduces itself

"Murali Krishna" <pmkrishna79@gmail.com> wrote in message
news:1152346314.050941.189810@35g2000cwc.googlegroups.com...


The question has already been answered, but I had to try out of curiosity.
This program gives a memory violation trying to write to memory on the 2nd
call to FuncP. I was sure it wouldn't work, but had to see what would
happen anyway.

#include <string>
#include <iostream>

int TestFunction()
{
    return 2;
}

typedef int (*Func)();

int main()
{
    Func FuncP;
    FuncP = TestFunction;

    int x = FuncP();

    std::cout << x << std::endl;

    FuncP = (Func)malloc( 1000 );
    memcpy( FuncP, TestFunction, 1000 );

    x = 4;
    x = FuncP(); // Crashes here

    free(FuncP);

    std::cout << x << std::endl;

    std::string wait;
    std::cin >> wait;

}