Re: delete an inherited class

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 27 Apr 2008 15:43:41 CST
Message-ID:
<52801dc4-bcb4-4343-b2aa-f5523625176a@f63g2000hsf.googlegroups.com>
On 27 Apr., 20:39, Free0...@gmail.com wrote:

if i make a class that inherit another class, when i delete the
pointer casted to the inherited class, only the destructor of the
inherited class fires, the base class does not.

ex:

class shape
{
 ~shape()
}

class square : class shape
{
 ~square()
}

square pSquare = new square();

shape pShape = dynamic_cast<shape *>(pSquare);

delete pShape; <== only calls ~shape()


Please ensure that code snippets are valid
C++, otherwise it's hard to distinguish what
your actual problem is. Let's first transform
this into syntactically valid C++ (Your comments
imply that your program compiles):

class shape
{
public:
  ~shape(){}
};

class square : public shape
{
public:
  ~square(){}
};

int main() {
   square* pSquare = new square();

   shape* pShape = dynamic_cast<shape *>(pSquare);

   delete pShape; // <== only calls ~shape()
}

Anything might happen in the very last statement,
because you are in "Undefined Behavior" land (something
like Alice's Wonderland, but not so funny ;-)

The rule behind this is [expr.delete]/3:

"In the first alternative (delete object), if the static
type of the operand is different from its dynamic type,
the static type shall be a base class of the operand?s
dynamic type and the static type shall have a virtual
destructor or the behavior is undefined.[..]"

In other words: If you want to perform a polymorphic
delete, the base class destructor must be virtual:

class shape
{
public:
  virtual ~shape(){}
};

HTH & Greetings from Bremen,

Daniel Kr?gler

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