Re: accessing parent class method

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Sun, 01 Jun 2008 07:57:59 GMT
On 2008-06-01 03:07, Victor Bazarov wrote:

ArbolOne wrote:

In my program I am using two classes foo1, the parent class, and foo2
the child class!
foo2 has overloaded inserter and extractor operator, but so does foo1!
How can I access foo1 inserter or extractor?

Post your code. It is easier when there is substance to the discussion.

Meanwhile, here is the example:

   struct foo {
       void foobar();

   struct bar : foo {
       void foobar();

   int main() {
       bar b;
       b.foobar(); // calls bar::foobar; // call foo::foobar

I would call it bad style to explicitly call a parent's implemenetation
of a function (and bad design if you have to), unless it is done in the
child's implementation of the same function:


struct foo1 {
  virtual void foobar() {
    std::cout << "foo1\n";

struct foo2 : public foo1 {
  virtual void foobar() {
    std::cout << "foo2\n";
    foo1::foobar(); // Call foo1's foobar()

int main() {
  foo1* f = new foo1();
  delete f;
  f = new foo2();

Erik Wikstr??m

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