Re: Question on auto_ptr, Which function will call first?

Hi, everyone, I'm studying the <<Thinking in C++>> volume Two.
In Chapter One, the example code : Auto_ptr.cpp
//-------------------------------------------------------
#include <memory>
#include <iostream>
#include <cstddef>
using namespace std;

class TraceHeap {
        int i;
public:
        static void* operator new(size_t siz) { //*****NOTE A
                void* p = ::operator new(siz);
                cout << "Allocating TraceHeap object on the heap "
                        << "at address " << p << endl;
                return p;
        }
        static void operator delete(void* p) {
                cout << "Deleting TraceHeap object at address "
                        << p << endl;
                ::operator delete(p);
        }
        TraceHeap(int i) //*******NOTE B
                : i(i)
        {
                ;
        }
        int getVal() const { return i; }
};

int main() {
        auto_ptr<TraceHeap> pMyObject(new TraceHeap(5));
        cout << pMyObject->getVal() << endl; // Prints 5
}
//------------------------------------------------------------------

My question is :

In My code: which code will be called first? The *NOTE A* or
*NOTE B* ? And Why?

I'm debugging through this code and found that *NOTE A* will called
first. Can someone explained it?

When I trace into the *new* function, the *siz* value is 4. I don't know
why it will be 4?