Re: std::string class instance are immutable or not??

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Fri, 06 Feb 2009 22:26:51 +0100
Message-ID:
<gmi9sh$dt1$1@reader.motzarella.org>
* SG:

On 6 Feb., 17:54, "Alf P. Steinbach" <al...@start.no> wrote:

* SG:

Assembling a string that way is very costly which is why in C# and in
Java you typically have a StringBuilder class which is like a string
but mutable.

I'm sorry but that is incorrect.


In Java it is the case (just tested on Sun's JVM/Compiler 1.6.0_10) by
wich I mean

   a = a + ".";

in a loop is horribly slow. You are supposed to use a
java.lang.StringBuilder for this.


I'm sorry but that is a misunderstanding and /very/ different from the example I
commented on.

It is however somewhat related, and using infix '+' is a very common newbie Bad
Coding Style (also reportedly employed by MS! :-) ), so I'll comment on it.

   a = a + ".";

is of necessity slow unless you have a supersmart optimizer, because it
constructs a separate new string instance. It therefore generally leads to
O(n^2) time when it's repeated in a loop. That is, the total time is
proportional to the /square/ of the final number of characters.

   a += ".";

is on the other hand the potentially fastest way to do concatenation, and with
any reasonable implementation of '+=' yields O(n) time.

*However*, with Java and C# it seems (as you found, and as also I found now when
repeating your testing) that '+=' is really ineffecient.

I.e., at least with the used compilers it seems that those languages have really
lousy '+=' operator implementations.

The difference between infix '+' and the '+=' update operator is what the 'a'
object can do, what knowledge it has of what's going on. With '+=' it only has
to make itself single reference (it it isn't already) and then append in its own
buffer. Which buffer, for a reasonable implementation, it then doubles in size
as necessary to achieve amortized O(n) behavior.

I'm not familiar with C#/.NET and it looks like there might be
compiler/VM magic involved w.r.t. the string class. So, yes, I can
imagine that in the .NET world string's "+=" isn't as bad as Java's
version.


Have you really tested Java's version of '+=' or have you tested infix '+'?

Anyways, my own testing, shown below, yields that unexpectedly bad result.

But the compiler and VM I used are old.

Still, what's the purpose of StringBuilder in C# if it wasn't
for speeding up string assembly.

With any reasonable string implementation '+=' is the most efficient possible
way to do concatenation, and since it avoids at least one conversion call it's
then more efficient than using a string builder (buffer) object.


I don't know what you mean by "conversion call" in this concext


Preparatory conversion from original string to string buffer, final conversion
from string buffer to string.

but ... Yes, I can imagine an implementation where string objects
share character buffers and only manage their own start/end pointers.


Yes, just about.

So, if there's some yet unused and big enough room left in that buffer
there's no need to allocate a new buffer for concatenation. But you
might need to do some locking/synchronization.


Only for the reference counting.

In Java there is also a String member function "concat" which could do
what I described above. Just for kicks and giggles I wrote a simple
test in Java:

1: String a = "";
   for (int k=0; k<0x10000; ++k) {
     a = a + ".";
   }

2: String a = "";
   for (int k=0; k<0x10000; ++k) {
     a = a.concat(".");
   }

3: StringBuilder sb = new StringBuilder();
   for (int k=0; k<0x10000; ++k) {
     sb.append(".");
   }
   String a = sb.toString();

   Test | Runtime
   -----+---------------
   1 | 10.369 seconds
   2 | 2.624 seconds
   3 | 0.076 seconds


#3 looks like C# not Java, and you're not testing '+='.

But I'm surprised at the results, which I've duplicated for both Java and C#,
and in particular for '+='.

Even though my compilers are old, it seems that both Java and C# have really
inefficient '+=' implementations.

As far as I know java.lang.StringBuilder doesn't do any kind of
locking/synchronization which is probably one reason it is so fast.

Alf, care to provide some C# test results just for the heck of it?


OK, but note that these are OLD compilers and VMs.

<versions>
C:\temp> java -version
java version "1.6.0_05"
Java(TM) SE Runtime Environment (build 1.6.0_05-b13)
Java HotSpot(TM) Client VM (build 10.0-b19, mixed mode, sharing)

C:\temp> csc
Microsoft (R) Visual C# 2005 Compiler version 8.00.50727.1433
for Microsoft (R) Windows (R) 2005 Framework version 2.0.50727
Copyright (C) Microsoft Corporation 2001-2005. All rights reserved.

fatal error CS2008: No inputs specified

C:\temp> g++ --version
g++ (GCC) 3.4.5 (mingw-vista special r3)
Copyright (C) 2004 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

C:\temp>
</version>

<code language="Java">
import java.util.Date;
import java.text.DecimalFormat;

class Time
{
     private long myMilliSecs;

     public Time()
     {
         myMilliSecs = new Date().getTime();
     }

     public long msecs() { return myMilliSecs; }
     public double secs() { return myMilliSecs/1000.0; }
}

class ConcatTest
{
     static final long n = 0x8000;

     static void doInfixAdd()
     {
         String a = "";
         for( int i = 1; i <= n; ++i )
         {
             a = a + ".";
         }
     }

     static void doConcatAdd()
     {
         String a = "";
         for( int i = 1; i <= n; ++i )
         {
           a = a.concat( "." );
         }
     }

     static void doBuilder()
     {
         StringBuffer sb = new StringBuffer();
         for( int i = 1; i <= n; ++i )
         {
             sb.append(".");
         }
         String a = sb.toString();
     }

     static void doUpdateAdd()
     {
         String a = "";
         for( int i = 1; i <= n; ++i )
         {
             a += ".";
         }
     }

     static void printResult( String s, Time start, Time end )
     {
         String num = new DecimalFormat( "00.00" ).format( end.secs() -
start.secs() );
         System.out.println( s + ": " + num );
     }

     public static void main( String[] args )
     {
         Time startTime;

         startTime = new Time();
         doInfixAdd();
         printResult( "Infix '+' ", startTime, new Time() );

         startTime = new Time();
         doConcatAdd();
         printResult( "concat ", startTime, new Time() );

         startTime = new Time();
         doBuilder();
         printResult( "builder ", startTime, new Time() );

         startTime = new Time();
         doUpdateAdd();
         printResult( "'+=' operator", startTime, new Time() );
     }
}
</code>

<results language="Java">
C:\temp> java ConcatTest
Infix '+' : 12,33
concat : 02,84
builder : 00,02
'+=' operator: 11,83

C:\temp> java ConcatTest
Infix '+' : 11,45
concat : 02,88
builder : 00,00
'+=' operator: 11,73

C:\temp> java ConcatTest
Infix '+' : 11,40
concat : 02,85
builder : 00,00
'+=' operator: 11,42

C:\temp>
</results>

<code language="C#">
using DateTime = System.DateTime;
using TimeSpan = System.TimeSpan;
using StringBuilder = System.Text.StringBuilder;

class ConcatTest
{
     private const long n = 0x8000;

     static void doInfixAdd()
     {
         string a = "";
         for( int i = 1; i <= n; ++i )
         {
             a = a + ".";
         }
     }

     static void doConcatAdd()
     {
         string a = "";
         for( int i = 1; i <= n; ++i )
         {
           a = string.Concat( a, "." );
         }
     }

     static void doBuilder()
     {
         StringBuilder sb = new StringBuilder();
         for( int i = 1; i <= n; ++i )
         {
             sb.Append( "." );
         }
         string a = sb.ToString();
     }

     static void doUpdateAdd()
     {
         string a = "";
         for( int i = 1; i <= n; ++i )
         {
             a += ".";
         }
     }

     static void printResult( string s, DateTime start, DateTime end )
     {
         string num = string.Format( "{0:00.00}", (end -
start).Milliseconds/1000.0 );
         System.Console.WriteLine( s + ": " + num );
     }

     static void Main()
     {
         DateTime startTime;

         startTime = DateTime.Now;
         doInfixAdd();
         printResult( "Infix '+' ", startTime, DateTime.Now );

         startTime = DateTime.Now;
         doConcatAdd();
         printResult( "concat ", startTime, DateTime.Now );

         startTime = DateTime.Now;
         doBuilder();
         printResult( "builder ", startTime, DateTime.Now );

         startTime = DateTime.Now;
         doUpdateAdd();
         printResult( "'+=' operator", startTime, DateTime.Now );
     }
}
</code>

<results language="C#">
C:\temp> concat
Infix '+' : 00,46
concat : 00,44
builder : 00,09
'+=' operator: 00,38

C:\temp> concat
Infix '+' : 00,43
concat : 00,40
builder : 00,00
'+=' operator: 00,74

C:\temp> concat
Infix '+' : 00,40
concat : 00,38
builder : 00,00
'+=' operator: 00,49

C:\temp>
</concat>

<code language="C++">
#include <iostream>
#include <iomanip> // std::fixed
#include <string>
#include <time.h> // clock

using namespace std;

long const n = 0x4000;

class TimeSpan
{
private:
     clock_t myTicks;
public:
     TimeSpan( clock_t ticks ): myTicks( ticks ) {}
     double secs() const { return double(myTicks)/CLOCKS_PER_SEC; }
};

class Time
{
private:
     clock_t myTicks;
public:
     Time(): myTicks( clock() ) {}
     TimeSpan operator-( Time const& rhs ) const { return myTicks - rhs.myTicks; }
};

void doInfixAdd()
{
     string a = "";
     for( int i = 1; i <= n; ++i )
     {
         a = a + ".";
     }
}

void doConcatAdd()
{
     string a = "";
     for( int i = 1; i <= n; ++i )
     {
       a = a.append( "." );
     }
}

// Not applicable.
//void doBuilder() {}

void doUpdateAdd()
{
     string a = "";
     for( int i = 1; i <= n; ++i )
     {
         a += ".";
     }
}

void printResult( string const& s, Time const& start, Time const& end )
{
     cout << fixed << setprecision( 4 );
     cout << s << ": " << (end - start).secs() << endl;
}

int main()
{
     Time startTime;

     startTime = Time();
     doInfixAdd();
     printResult( "Infix '+' ", startTime, Time() );

     startTime = Time();
     doConcatAdd();
     printResult( "concat ", startTime, Time() );

     startTime = Time();
     doUpdateAdd();
     printResult( "'+=' operator", startTime, Time() );
}
</code>

<results language="C++">
C:\temp> a
Infix '+' : 0.0940
concat : 0.0000
'+=' operator: 0.0000

C:\temp> a
Infix '+' : 0.1560
concat : 0.0000
'+=' operator: 0.0000

C:\temp> a
Infix '+' : 0.0930
concat : 0.0000
'+=' operator: 0.0000

C:\temp>
</results>

So, in summary, at least for C++ programming it is, as I noted earlier, a really
good idea to use '+=' (or equivalently 'append') instead of infix '+', and a
really bad idea to do the opposite. And it is surprising that the Java and C#
compilers don't implement '+=' efficiently; it's easy to do. I thought they did.

Cheers & hth.,

- Alf

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