Re: Storing an array's subscript into a structure's member

From:
"Ben Voigt [C++ MVP]" <rbv@newsgroups.nospam>
Newsgroups:
microsoft.public.vc.language
Date:
Mon, 27 Jul 2009 12:39:30 -0500
Message-ID:
<71E60805-2BB9-4865-BC77-EDBA776D99E1@microsoft.com>
"Robby" <Robby@discussions.microsoft.com> wrote in message
news:C693F9EF-A69B-4A33-8FF6-9EA36A64AF9C@microsoft.com...

Alex........ GOT IT !

========================================
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct tag_lb
{
long (*pmr)[5];


Yup, you've preserved the "length of each row" information that Scott warned
you the compiler needs for two-dimensional indexing, now everything is going
to work right.

}lb;

lb* create_obj(long (*pmr)[5])
{
lb *ptr_lb = NULL;

ptr_lb = malloc (sizeof *ptr_lb);
ptr_lb->pmr = pmr;
return ptr_lb;
}

void f1(lb *pObj)
{
long t;

t = pObj->pmr[0][0];
t = pObj->pmr[0][1];
t = pObj->pmr[0][2];
}

int main()
{
lb *pObj = NULL;

long pmr[][5] = { {195, 194, 193, 111, 111 },
{194, 195, 112, 222, 111 } };

pObj = create_obj(&pmr[0]);
f1(pObj);
free(pObj);
return 0;
}
===================================

&pmr[0] where &pmr[0] is the address of the array's innitial base address
of
the array. And it mathes the type of (long (*pmr)[5])

I am still digesting this one..... Thanks again Alex and everyone else!

--
Best regards
Roberto

"Alex Blekhman" wrote:

"Robby" wrote:

The basic difference is that I type casted the prm type to a
long* type.


Yes, cast will silent the compiler, but you'd better fix the
types, so the problem won't bite you at the runtime. Here's good
overview of arrays and pointers in C:

"Section 2. Arrays and Pointers"
http://www.lysator.liu.se/c/c-faq/c-2.html

Alex

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