Re: The joy (?) of C++98 argument forwarding

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Tue, 04 May 2010 15:01:49 +0200
Message-ID:
<hrp5vq$uk8$1@news.eternal-september.org>
On 04.05.2010 14:56, * DeMarcus:

Alf P. Steinbach wrote:

Consider ...

<code>
// Copyright (c) Alf P. Steinbach, 2010.
#include "_config.h"

#include <progrock/cppx/pointers/Shared.h>
#include <iostream>

namespace {
using namespace progrock;

cppx::Size count = 0;

class Foo
{
protected:
~Foo()
{
using namespace std;
--count;
cout << "Foo destroyed" << endl;
}

public:
Foo()
{
using namespace std;
cout << "Foo constructed" << endl;
++count;
}

Foo( int x )
{
using namespace std;
cout << "Foo constructed with arg " << x << endl;
++count;
}

Foo( int x, char const s[] )
{
using namespace std;
cout << "Foo constructed with args " << x << " and \"" << s << "\"" <<
endl;
++count;
}
};

void test()
{
using namespace cppx;

Shared< Foo > r1 = newObject();
assert( count == 1 );

Shared< Foo > r2( r1 );
assert( count == 1 );

Shared< Foo > r3( newObject(), args( 42 ) );
assert( count == 2 );

Shared< Foo > r4( newObject(), args( 42, "blah blah" ) );
assert( count == 3 );

r4 = r2;
assert( count == 2 );

r3 = r2;
assert( count == 1 );

r3 = r3;
assert( count == 1 );
}
}; // namespace anon

void testShared()
{
test();
assert( count == 0 );
}
</code>

Is the notation in the 'test' routine OK, or would it be better (in
some sense) with some macro, e.g. like

Shared< Foo > r( CPPX_NEW_SHARED( 42, "blah blah" ) );

?


At least consider CPPX_NEW_SHARED_FOO( 42, "blah blah" ). Otherwise the
macro name would be as non-intuitive as

CPPX_NEW_SHARED( PI, 21.45, time() )


Well for the example above the type is implicit in the declaration, so it would
be redundant to repeat it there.

On the other hand you have a point -- I didn't think of it -- for an actual
argument in a routine call.

On the third hand, we usually don't specify arguments there for value arguments.

Can't you do the wrapper with a template instead of a macro?


Not sure what you mean; the Shared shared pointer type is templated, as the
example usage code shows.

Cheers,

- Alf

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