Re: derived class and virtual function

From:
red floyd <no.spam.here@its.invalid>
Newsgroups:
comp.lang.c++
Date:
Tue, 17 Aug 2010 16:54:57 -0700
Message-ID:
<i4f7gh$ar9$1@news.eternal-september.org>
On 8/17/2010 1:54 AM, James Kanze wrote:

On Aug 13, 10:09 am, "Francesco S. Carta"<entul...@gmail.com> wrote:

Francesco S. Carta<entul...@gmail.com>, on 13/08/2010 10:39:51, wrote:

subramanian10...@yahoo.com, India<subramanian10...@yahoo.com>, on
13/08/2010 01:29:13, wrote:

In Stanley Lippman's 'C++ Primer Fourth Edition', in page 564, the
following is mentioned:

"A virtual function in the derived class can return a reference or
pointer to a class that is PUBLICLY derived from the type returned by
the base class function."

I am unable to understand this sentence. Kindly explain it with
program sample.


IIUIC, that means that if you have a function with signature "virtual
Base* Clone() const;" in the base class, then the implementation of the
same function in the derived class can be: "Base* Clone() const { return
new Derived(*this); }" - just an example that assumes Derived is
copy-constructible, of course.


There is either something wrong in that sentence, in my understanding
or in my compiler - or my settings thereof - because it allows me to
return a pointer to Derived where Base is private:


In your understanding, I think, because...

//-------

#include<iostream>

using namespace std;

class Base {
      public:
      Base(int data = 0) : data(data) {};
      Base(const Base& base) : data(base.data) {};
      virtual Base* Clone() const {
          cout<< "cloning Base"<< endl;
          return new Base(*this);
      }
      int Data() const {
          return data;
      }
      private:
      int data;
};

class Derived : private Base {
      public:
      Derived(int data = 0) : Base(data) {};
      Derived(const Derived& derived) : Base(derived) {};
      Base* Clone() const {


Here, you're still returning a Base. Any conversion takes place
in Derived (where the derivation is visible).

Try changing the return type to Derived*; the compiler should
complain then.

See ?10.3/5 in the standard for details.


James, I thought that the compiler should *not* complain if the
return type of Derived::Clone was Derived*. Isn't that a
covariant return type?

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Leon De Poncins, p. 123)