Re: overloading operator delete[](void*, size_t) - possibly incorrect implementation of the language specification in Visual C++?

From:
red floyd <redfloyd@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 26 Dec 2010 20:02:31 CST
Message-ID:
<63713cd1-0822-40b7-8557-eac2ff44f28d@f20g2000prn.googlegroups.com>
On Dec 25, 12:04 pm, Dobi <ha...@daiw.de> wrote:

On Dec 22, 3:36 am, Chris Vine <ch...@cvine--nospam--.freeserve.co.uk>
wrote:> But does it do it if you don't hand off to global operator

new[]()/delete[]() and instead, say (for test purposes), run the
original poster's test with an allocator which returns a static array?

If it does give the same result then this seems to me to be a definite
non-compliance with the standard, and someone should report the bug.

Chris


For testing this I replaced
return ::operator new[]( s );
with
static int mem[100]; return &mem[0];
and the result is still the same:
delete[]: size_t=4
So i reported it tohttps://connect.microsoft.com/VisualStudio/feedback/details/631380/ov...
of-the-language-specification-in-visual-c
and I am looking forward to the answer of the compiler developers.


It looks like the size_t parameter is the size of the object instead
the number of bytes allocated.

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