Re: Forward template declaration problem

I'd like to hide implementation details from declaration because
dragging all the support types from .cpp to .h would be unnecessary,
redundant and just plain ugly.
So I try to forward-declare the classes used in actual
implementation. This works well for ordinary classes, but not so
well for templates (std::multimap in this case).

I know the typedef from the following sample redeclares my desired
type, but I included the code because I don't know any better. I
also included a sample for MyClass class which compiles fine - for
reference of what I want to do.

So how can I make the below code work without:
1. Dragging all the necessary types into .h
2. Declaring jobList member as void * and then typecasting all over
the place
3. Using #define to mask the typecasting from #2

Please forgive the fact that I'm still learning C++.

Thanks,
Jure

//sample.h here
class JobListMap;
class MyClass;

class RefClock
{
public:
 RefClock();
 JobListMap *jobList;
 MyClass *test;
};

//sample.cpp from now on
#include "sample.h"
#include <map>

struct MyType1 {
...
};
struct MyType2 {
...
};
class MyClass {
};

typedef std::multimap<MyType1, MyType2> JobListMap;

RefClock::RefClock()
{
 jobList = new JobListMap();
 test = new MyClass();
}