Re: tr1 and shard_pointer for arrays?

From:
Howard Hinnant <howard.hinnant@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 24 Dec 2008 14:21:38 CST
Message-ID:
<046c8b12-29bc-4819-8978-79bc99ecea34@s14g2000vbp.googlegroups.com>
On Dec 22, 10:48 pm, "Siegfried Heintze" <siegfr...@heintze.com>
wrote:

One of the many annoying things are about std::auto_ptr is that it
could
only point to a scalar.

Can std::tr1::shared_ptr point to a non-scalar? Anyone show me a
quickie
example for an array of X where X has a destructor?

Thanks,
Siegfried

Here is my attempt. It dies

#include<memory>
#include <array>

template<typename T>
struct Y
{
   Y():y_(){ cout<<"Y ctor="<<y_<<endl; }
   Y(T y):y_(y){ cout<<"Y ctor="<<y_<<endl; }
   Y(const Y& s):y_(s.y_){}
   Y& operator=(const Y& s){ y_ = s.y_; cout << "Y op=" << y_ <<
endl; return *this; }
   ~Y(){ cout << "Y dtor="<<y_<<endl; }
   T y_;
   template<typename CHAR> friend std::basic_ostream<CHAR>& operator<<
   (const std::basic_ostream<CHAR>& os, const Y<T>& Y) { return os
<< Y.y_; }};

int main(int argc, char**argv){
   shared_ptr<Y<int> > pA(new Y<int>[3]);
   return 0;

}


Here's one solution:

template <class T>
struct my_delete
{
    my_delete() {}
    template <class U> my_delete(const my_delete<U>&) {}
    void operator() (T* ptr) const {delete ptr;}
};

template <class T>
struct my_delete<T[]>
{
    void operator() (T* ptr) const {delete [] ptr;}
private:
    template <class U> void operator() (U*) const;
};

int main()
{
   shared_ptr<Y<int> > pA(new Y<int>[3], my_delete<Y<int>[]>());
}

C++0X will come with a std::default_delete<T[]> which can be used like
this.

-Howard

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