Re: when delete do not call destructor

From:

"Daniel T." <daniel_t@earthlink.net>

Newsgroups:

comp.lang.c++

Date:

Thu, 05 Mar 2009 19:52:21 -0500

Message-ID:

<daniel_t-D7882F.19522105032009@earthlink.vsrv-sjc.supernews.net>

S S <sarvesh.singh@gmail.com> wrote:

I can not write full code as it is 20000 lines kind of copywrite
thing. But I am writing below required details,
class A{
public:
void *operator new(size_t, void *p) {return(p);}

void *operator new(size_t n) throw(std::bad_alloc)
{ My_allocation_routine(&someInternalVar, n);}

void operator delete(void* p, size_t n) {My_deallocation_routine(p,
n);}
..
..
~A() {}
};

I did,

A* obj = new A;
delete obj;

I set breakpoint in destructor of this class, it does not reach there.
Don't know why?

I tried the following:

#include <iostream>

using namespace std;

void* My_allocation_routine(int* i, size_t n)
{
   cout << "My_allocation_routine\n";
   return malloc(n);
}

void My_deallocation_routine(void* p, size_t n)
{
   cout << "My_deallocation_routine\n";
   if (p)
      free(p);
}

class A
{
   static int someInternalVar;
public:
   void *operator new(size_t, void *p)
   {
      return(p);
   }

   void *operator new(size_t n) throw(std::bad_alloc)
   {
      return My_allocation_routine(&someInternalVar, n);
   }

   void operator delete(void* p, size_t n)
   {
      My_deallocation_routine(p,n);
   }

   ~A()
   {
      cout << "in d_tor\n";
   }
};

int A::someInternalVar = 0;

int main()
{
   A* obj = new A;
   delete obj;
}

The output was as follows:

My_allocation_routine
in d_tor
My_deallocation_routine