Re: Overload operator

From:
=?iso-8859-1?q?Erik_Wikstr=F6m?= <eriwik@student.chalmers.se>
Newsgroups:
comp.lang.c++
Date:
16 May 2007 06:56:18 -0700
Message-ID:
<1179323778.261907.323830@y80g2000hsf.googlegroups.com>
On 16 Maj, 15:10, ek <eksa...@yahoo.com> wrote:

In the class below I overload the "()" operator. When reading an
element in an int array "()" is therefore used. But why can't I still
use "[]" when writing something like a[2] = 4;

class MyArray {
public:
        MyArray(int a) : data(new int[a]){}

        ~MyArray() {delete[] data;}

        int& operator()(int a){
                return data[a];
        }

        int operator()(int a) const{
                return data[a];
        }

private:
        int* data;

};

When overloading "()" the normal "[]" operator no longer works. I can
instead do the assignment with Arr(2) = 5; but I have not specified an
overload of "()" that does assignment, why is that not needed?


This one takes care of the assignment:

        int& operator()(int a){
                return data[a];
        }

It returns a reference to the element so when you assign to the
reference you assign to the element.

--
Erik Wikstr=F6m

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