Re: Overload operator * as member function.

Thomas Maeder <>
Sun, 12 Jul 2009 05:56:45 CST
AY <> writes:

I'm trying to multiply two class objects as member function using
operator * . For some reason MVC++ compiler refuses to compile the
below code when defined as member function.

FWIW, I think it's safe to say that in general, overloading this
operator as a non-member is considered by many to be the preferable

However, if the operator* is implemented as non-member function it
compiles fine. Here is the code snippet [ courtesy - " Effective C++
- Scott Myers " ]

class A

        A(int n =0, int d=1): num(n),den(d){}

        //const A operator*(const A& rt, const A& lt) const;

        // Why does it not compile within the class?
        // How come it compiles fine outside of the class?

        const A operator*(const A& rt, const A& lt)
            return A(rt.denominator()*lt.denominator(),

Well, if operator*() is a member function, one of the operands is the
object it's applied to. So the parameter list should only have one

On the other hand, you should declare the operator const. Did you mean
to do that when you wrote const in front of the declaration?


A &operator*=(A const &rt)
   den *= rt.den;
   num *= rt.num;
   return *this;

and then

A operator*(A const &rt) const
   A result(*this);
   result *= rt;
   return result;

      [ See for info about ]
      [ comp.lang.c++.moderated. First time posters: Do this! ]

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