Re: Passing array by reference

"Victor Bazarov" <>
Wed, 18 Jul 2007 13:29:08 -0400
john wrote:


quick question - got a function like:

void CalculateApproach(float (&Params)[4], double (&ObjectPos)[3],
double (&VehiclePos)[4], double (&NewPos)[4])

OK, the seconds argument should come from an array but this array is
bigger than the expected 3 i.e it has 10 elements but I only need 4,5
and 6 so I tried something like:

CalculateApproach(fAppParams, &dFeatures[4], dCurVehPos, dNewVehPos);

but it fails for me. Am I trying to do something that is not allowed

Yes, essentially.

and hence should just make new array[3] and copy my values in and
then pass it into the function or can someone give me hint towards
the syntax i should be using if it can work?

You could try forcing it with a cast...

void foo(int (&ar)[3])
    ar[0] = 1;
    ar[1] = 11;
    ar[2] = 111;
#include <cassert>
int main()
    typedef int (*pArrayOf3int)[3];
    int array[10] = {};
    foo(*pArrayOf3int(array + 5));
    assert(array[5] == 1);
    assert(array[6] == 11);
    assert(array[7] == 111);

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