Re: No polymiorphism for virtual operator= ?
* sun1991:
to make it work, you have to do this:
class Fraction2: public Fraction
{
public:
Fraction2(int num1, int num2, int num3):
Fraction(num1, num2),
m_num3(num3){}
virtual Fraction& operator=(const Fraction& f);
private:
int m_num3;
};
but this really doesn't make too much sense.
Yeah, I got your point. Thanks. I used different parameter in
operator=, so it becomes two different function. Can I say that don't
expect virtual operator= to be polymiorphism, because it is not the
way you want? (Sounds like a C++ philosophy question)
If you keep the signature the same (as in the code shown above) in the
derived class, then you have a polymorphic assignment operator. It's an
assignment operator but it's not the copy assignment operator; you can
have as many assignment operators as you want in addition to the copy
assignment operator. When the copy assignment operator is not declared,
and is needed, the compiler generates a copy assignment operator.
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