Re: Virtual operator overloads don't seem to work?

From:
Stuart Brockman <stuartbrockman@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 23 Oct 2008 00:13:09 -0700 (PDT)
Message-ID:
<3c2101a9-038c-4c2b-9f64-c9bfe053a8f9@d70g2000hsc.googlegroups.com>
On 22 Oct, 23:29, Sam <s...@email-scan.com> wrote:

Stuart Brockman writes:

Hi,
I don't quite get what is going on in this code example:

---------------------------
#include <iostream>

using namespace std;

class Base{
public:
    virtual void Test(){
        cout << "Base" << endl;
    }

    virtual bool operator==(const Base &other){
        cout << "Base Comparison" << endl;
        return false;
    }
};

class Derived : public Base{
public:
    void Test(){
        cout << "Derived" << endl;
    }

    bool operator==(const Derived &other){
        cout << "Derived Comparison" << endl;
        return true;
    }
};

int main(int argc, char** argv) {
    Base a; //Create a base object
    a.Test(); //Outputs "Base" as expected
    Derived b, c; //Create two derived objects
    b.Test(); //Outputs "Derived" as expected
    if(b==c) cout << "True" << endl; //Does derived comp=

arison and

returns true as expected.
    Base *d=&b, *e=&c; //Create two base pointers to derived=

 objects

    d->Test(); //Outputs "Derived" as expected
    if(*d==*e) cout << "True" << endl; //Does base compariso=

n and

returns false!?
    return 0;
}
----------------------------
The output is:

Base
Derived
Derived Comparison
True
Derived
Base Comparison

Notice, that the line "d->Test()" works correctly, but the comparison
on the next line does not. The compiler (g++ (GCC) 4.2.3 (Ubuntu
4.2.3-2ubuntu7) ) seems to be ignoring the virtual-ness of
Base::operator== .


That's because "bool operator==(const Derived &)" does not polymorphi=

cally

overload "bool operator==(const Base &)". In a derived class, the fun=

ction's

signature must match the base class's virtual function, in order for it t=

o

be polymorphically overloaded (the function parameters must match). In yo=

ur

case, above, you have two different functions, no different that void foo=

()

and void bar(). One does not overload the other.

                       Is this correct?


Yes.

                                   =

     Have I made a mistake?

Yes, but a very natural one.

 application_pgp-signature_part
< 1KViewDownload


Ahh... I see... So what should I change Derived::operator== to?
Clearly it would have to have a signature of bool
Derived::operator==(const Base &other), but how do I make sure that I
get correct behavior when doing a "Derived==Base" (I would prefer that
Base::operator== was called in this case)?

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