Re: binding a member function with an argument of reference type

From:

Triple-DES <denplettfrie@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Sun, 18 Oct 2009 23:23:16 -0700 (PDT)

Message-ID:

<2b8aac2e-0b83-49c8-99bf-6d5c25bb837e@a32g2000yqm.googlegroups.com>

On 17 Okt, 17:29, Maxim Yegorushkin <maxim.yegorush...@gmail.com>
wrote:

On 16/10/09 14:24, Triple-DES wrote:

Submitted for your consideration:

#include<functional>

struct C { void f(const int&) {} };

template<typename F>
void call(F f)
{
   f(123);
}
int main()
{
   using namespace std;
   C c;
   call ( bind1st(mem_fun(&C::f),&c) );
}

This seemingly fails on most implementations because the library
attempts to form a reference to a reference. Is it possible to bind
this function using only the C++03 standard library utilities?

Only if you don't use reference arguments.

Use boost::bind(). It does not have this problem:

call(boost::bind(&C::f, &c, _1));

Thanks Maxim. Unfortunately, the Boost licensing scheme is
unacceptable for our application. I ended up writing my own wrapper
function object. That's roughly 15 lines of (potentially buggy) code,
that I am only going to use for this very specific task. Not an ideal
solution.