Re: Why you should never use a const& parameter to initialize a const& member variable!

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Fri, 5 Feb 2010 04:32:45 CST
Message-ID:
<60bcb115-fe51-4dc7-b10e-8fa2bc1fc32b@a32g2000yqm.googlegroups.com>
On 4 Feb., 14:17, "Martin B." <0xCDCDC...@gmx.at> wrote:

Daniel Kr?gler wrote:


[..]

While I agree that this *can* cause a problem,
I still use references to const in examples
like yours - in C++03 you have to take care here.
I say so, because there are numerous places,
where this could cause problems - just remember
a call of the std::min or std::max functions.
If the compared objects are really large one's
I don't want to copy them, therefore I may want
to get the result by reference (to const) as well.


I'm not entirely sure what you mean here. My Better object still only
uses a const& member, but the initialization is done via a pointer. So
the performance should be exactly the same?


I didn't want to imply that const& is more efficient
than your pointer approach. I only wanted to highlight
that your constructor situation belongs only to one
family of these problems. I don't assume that you
want suggest that std::min should take arguments
by pointer as well, or do you?

In C++0x there is a nice way of preventing the
problem you mention: Just add an overload of the
corresponding function which accepts an rvalue
reference of the type and define the function
as deleted:

class Bad {
         int const& tracker_;
public:
         explicit Bad(int const&&) = delete;
         explicit Bad(int const& to_track)
         : tracker_(to_track)
         { }

      [...]
};


I've never worked with C++0x. Am I correct in assuming that the deleted
function binds to temporaries (like fn return value or implicit
temporary from say a short or char) first and then the one that binds to
non-temporaries isn't considered anymore by the compiler?


That comes near. What happens is the following:
Given your example with rvalues as arguments
the compiler performs overload resolution
given the two constructors. For rvalues, the
deleted constructor overload will be selected.

*If* a deleted function is selected by
overload resolution (or by other way that would
refer to that function), the program becomes
ill-formed, which requires a diagnostic
("compile error" in our usual way of describing
the compiler's behavior).

HTH & Greetings from Bremen,

Daniel Kr?gler

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