std::move for existing standard

From:
Jonathan Lee <jlee975@uwo.ca>
Newsgroups:
comp.lang.c++
Date:
Tue, 29 Jun 2010 08:07:05 -0700 (PDT)
Message-ID:
<564e7270-8a09-47cf-a106-ef28b2b7c8c7@e5g2000yqn.googlegroups.com>
Hi all,
  I want to begin using move semantics in my code assuming
only the current standard. I thought I could provide move
constructors and assignments by typedef-ing rvalue references
to "moveType" when C++0x is available, and otherwise using
a proxy "movable" class. Just to make the transition easier.
Example below.

Any thoughts?

--Jonathan

// begin: movetest.cpp
#include <cstddef>
#include <algorithm>

#if (__cplusplus > 199711L)
// Use the C++0x std::move if available
#include <utility>
namespace cpp0x = std;
#else
// Older versions of C++ use proxy class
namespace cpp0x {

template<class T>
class movable : public T {
public:
  movable(T& t):T() { T::swap(t); }
};

template<class T>
movable<T> move(T& t) {
  // rely on RVO
  return movable<T>(t); }

}
#endif

class dummy {
  char* ptr;
  std::size_t len;
public:
  #if (__cplusplus > 199711L) /* c++0x */
  typedef dummy&& moveType;
  #else
  typedef cpp0x::movable<dummy>& moveType;
  #endif

  dummy(): ptr(0), len(0)
    { }
  dummy(std::size_t n):ptr(n ? new char[n] : 0), len(n)
    { }
  dummy(const dummy& d):ptr(d.len ? new char[d.len] : 0), len(d.len)
    { }
  dummy(moveType d):ptr(d.ptr), len(d.len) {
    d.ptr = 0, d.len = 0;
  }

  dummy& operator=(moveType d) {
    d.swap(*this);
    return *this;
  }

  void swap(dummy& d) {
    std::swap(ptr, d.ptr);
    std::swap(len, d.len);
  }
};

int main () {
  dummy a(5);
  dummy b;

  b = cpp0x::move(a);

  return 0;
}
// end: movetest.cpp

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