ill-formed reference to pointer

From:
m0shbear <andrey.vul@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 29 Jan 2011 21:03:57 -0800 (PST)
Message-ID:
<d4cc69ae-b11a-4fee-84e0-0cbc5968dd59@k30g2000yqb.googlegroups.com>
I'm trying to use this code to check the compiler's output to see if
the inlining is aggressive enough to use inline functions instead of
#defines and I'm getting the following error: "invalid initialization
of reference of type =91const unsigned char*&' from expression of type
=91u8*'".
Does the inline lowercase match the macro uppercase?

code:
extern "C" {
#include <stdint.h>
}

typedef uint8_t u8;
typedef uint64_t u64be;

template <typename T>
struct itype {
    typedef T value;
    typedef T& reference;
    typedef T const& const_reference;
    typedef T* pointer;
    typedef T const* const_pointer;
};

#define PTR_CAST(T, p) (reinterpret_cast<T*>(p))

#define XF64(dst,src) *PTR_CAST(u64be,dst) ^= *PTR_CAST(u64be
const,src); (src) += 8

template<typename T, typename P> inline T* ptr_cast(P* p) { return
reinterpret_cast<T*>(p); }

inline void xf64(itype<u8>::pointer dst,
itype<itype<u8>::const_pointer>::reference src) {
    *ptr_cast<u64be>(dst) ^= *ptr_cast<u64be const>(src); src += 8;
}

int main() {
    u8 fop[64], foq[64], fos[64],fot[64];
    u8* foP=fop;
    u8* foQ=foq;
    u8* foS=fos;
    u8* foT=fot;
    xf64(foP,foQ);
    XF64(foS, foT);
}

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