Re: ill-formed reference to pointer

From:

Ian Collins <ian-news@hotmail.com>

Newsgroups:

comp.lang.c++

Date:

Sun, 30 Jan 2011 18:38:25 +1300

Message-ID:

<8qkbqiFpaaU1@mid.individual.net>

On 01/30/11 06:03 PM, m0shbear wrote:

I'm trying to use this code to check the compiler's output to see if
the inlining is aggressive enough to use inline functions instead of
#defines

It's highly unlikely that you would have to resort to macros, unless
your compiler is very old and scummy.

and I'm getting the following error: "invalid initialization
of reference of type ?const unsigned char*&? from expression of type
?u8*?".

That's right, the types don't match.

Does the inline lowercase match the macro uppercase?

Not really, macro arguments don't have types.

code:
extern "C" {
#include<stdint.h>
}

You shouldn't have to add the extern "C" here.

typedef uint8_t u8;
typedef uint64_t u64be;

These are horrible!

template<typename T>
struct itype {
    typedef T value;
    typedef T& reference;
    typedef T const& const_reference;
    typedef T* pointer;
    typedef T const* const_pointer;
};

#define PTR_CAST(T, p) (reinterpret_cast<T*>(p))

Why do this?

#define XF64(dst,src) *PTR_CAST(u64be,dst) ^= *PTR_CAST(u64be
const,src); (src) += 8

template<typename T, typename P> inline T* ptr_cast(P* p) { return
reinterpret_cast<T*>(p); }

Or this?

--
Ian Collins