Re: plz xplain behavior of const_cast

From:
Goran <goran.pusic@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 4 Jan 2012 23:55:14 -0800 (PST)
Message-ID:
<f4535787-17da-43df-b773-295015f60c56@z1g2000vbx.googlegroups.com>
On Jan 5, 8:01 am, Heck <heckja...@ordertostymieharvestersverizon.net>
wrote:

 const int NUM_UNIVS = -1;

{
   // some block of code, and at the end of the block,
   // I now have the value I need for NUM_UNIVS,
   // so I do the following to assign it the new value

   int * tmp;
   *(tmp = const_cast <int*> (& NUM_UNIVS)) = new_value;


This is where your code is broken. It is undefined behavior to use
const_cast to cast the const away from a const object, and &NUM_UNIVS
is const int*. Everything else stems from there, see below.

You can only use const_cast on variables that were __initially__
defined as non const. So for example, this is OK:

int i=1;
const int& r = i;
const_cast<int&>(r) = 2;

(Note the use of int&, not int*, to lower syntactical gibberish.)

}

Then, I begin the operations that require NUM_UNIVS, but, this first
condition was failing upon its very first test and the loop was of
course being skipped:

for( univ_num = 0; univ_num <= NUM_UNIVS; ++univ_num)
{
  ...

The assembly language showed that, indeed, where I expected there to
be a reference to the new value of NUM_UNIVS from the stack, there was
no such. Instead the cmp was made with a -1 literal.


Yes. You said that NUM_UNIVS is const, and equals -1. So compiler took
the freedom to replace it with -1, which is a common optimization.
This, again, is a consequence of language rule that const_cast is
legal only if done on an object (or a reference to it) that was
defined as non-const.

The rule is good, and you broke it ;-). Further, in C++, there's no
reason for the contortion you tried. I am guessing that you want
NUM_UNIVS to be seen as const to a (significant) part of your code,
but you want to change it in some other parts. You can solve that
problem in a different way. For example:

file1.cpp

namespace { int NUM_UNIVS=-1; }
const int& NumUnivs = NUM_UNIVS;
int NumUnivs() { return NUM_UNIVS; }

void ChangesNumUnivs()
{
 workworkwork;
 NUM_UNIVS=9;
}

file1.h
extern const int& NumUnivs; // Use this to access a read-only variant
of NUM_UNIVS.

file2.cpp
#include file1.h
void f()
{
 for (int i=0; i<NumUnivs; i++)
  workworkwork;
}

Goran.

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