Re: Revistiing using return value as reference

From:
=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 26 Dec 2007 11:33:30 GMT
Message-ID:
<e_qcj.2049$R_4.1547@newsb.telia.net>
On 2007-12-26 06:01, johanatan wrote:

On Dec 25, 3:00 pm, "Jim Langston" <tazmas...@rocketmail.com> wrote:

Foo& Bar( int Val )
{
   return Foo( Val );

}

Will not work, can not convert Foo to Foo&


Should work, but not a very useful thing to do as local copy dies
immediately.


Should not work, a reference can not bind to a rvalue.

Foo Bar( int Val )
{
   return Foo( Val );

}

int main()
{
   Foo& Inst = Bar( 10 );

}

Does not work, same thing, can not convert Foo to Foo&.


Should also work. Something else is going on as that syntax is
compiling fine in my compiler.


Get a new compiler. Once again, you can not bind a reference to a rvalue.

Foo& Bar(int Val )
{
   Foo Temp( Val );
   return Foo( Val );

}


I think you meant to return Temp, no? That too should work, but as
with #1, isn't very useful.


Invoking undefined behaviour I would think.

--
Erik Wikstr?m

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