Re: Occurence problem: different ideas

From:
"Mike Wahler" <mkwahler@mkwahler.net>
Newsgroups:
comp.lang.c++
Date:
Sun, 07 May 2006 20:33:21 GMT
Message-ID:
<lQs7g.1104$u4.1051@newsread1.news.pas.earthlink.net>
"utab" <umut.tabak@gmail.com> wrote in message
news:1147023768.882586.288170@y43g2000cwc.googlegroups.com...

Dear all,

I tried to solve the occurence problem: to find the distinct occurences
of a word in an input. I know that I could use map and other STD lib
functions.


Then why don't you?

I tried to do it the hard way.


Why?

I tried sth and it is working
but I could not structure my algorithm very well so I had to add some
more lines after thinking it on a paper draft. I am posting the whole
code and waiting different ideas.


My idea is to use those tools suited for a particular purpose,
e.g. a map in this case.

First I sorted them with the sort function, after that they are in
nondecreasing order(and also grouped by this way) and then I have
counted the number of items in these groups by checking whether I am at
the end or not


See below.

     1 #include <iostream>
     2 #include <algorithm>
     3 #include <string>
     4 #include <vector>
     5 int main(){
     6
     7 std::string x;
     8 std::vector<std::string> input;
     9 std::vector<std::string> sorted_input;
    10 std::vector<std::string> words;
    11 std::vector<int> counts;
    12 std::vector<std::string>::size_type vec_sz;
    13 int count=1;
    14
    15
    16 while(std::cin >> x)
    17 input.push_back(x);
    18
    19 sort(input.begin(),input.end());
    20
    21 std::string test=input[0];
    22
    23 vec_sz=input.size();
    24
    25 for(int i=0;i!=vec_sz;++i)
    26 std::cout << input[i] << std::endl;
    27
    28
    29 for(int k=1;k!=vec_sz;++k){
    30
    31 if(input[k]==test){
    32 ++count;
    33 if(k==vec_sz-1){
    34 words.push_back(test);
    35 counts.push_back(count);
    36 }
    37 }
    38 else{
    39 words.push_back(test);
    40 counts.push_back(count);
    41 test=input[k];
    42 count=1;
    43 if(k==vec_sz-1){
    44 words.push_back(test);
    45 counts.push_back(count);
    46 }
    47 }
    48 }
    49
    50 vec_sz=words.size();
    51 std::cout << "WORDS" <<"\t"<<"OCCURENCE#"<<std::endl;
    52 for(int i=0;i!=vec_sz;++i)
    53 std::cout << words[i]<<"\t" << counts[i]<<
std::endl;
    54
    55 return 0;
    56
    57 }


#include <ios>
#include <iostream>
#include <map>
#include <string>

int main()
{
    std::map<std::string, std::streamsize> m;
    std::string word;

    std::cout << "Enter data: ";

    while(std::cin >> word)
        ++m[word];

    std::map<std::string, std::streamsize>::
        const_iterator it(m.begin());

    const
    std::map<std::string, std::streamsize>::
        const_iterator en(m.end());

    while(it !=en)
    {
        std::cout << it->first << " occurs "
                  << it->second << " times.\n";
        ++it;
    }

    return 0;
}

Test run:
--------------------------------------------------------------------------------
Enter data: In base class, I have a function "Initialize(int a)". In the
derived

class , I need the funciton "Initialized" to do more things, therefore
I redefined the function as "Initialize(int a, int b)".

Now I want the Derived::initialize to include all the operations
contained in Base::initialize. Are there and simple ways to do that?
Currently, I just copy all the codes in Base::initialize to
Derived::initialize.

Thanks.
^Z
"Initialize(int occurs 2 times.
"Initialized" occurs 1 times.
, occurs 1 times.
Are occurs 1 times.
Base::initialize occurs 1 times.
Base::initialize. occurs 1 times.
Currently, occurs 1 times.
Derived::initialize occurs 1 times.
Derived::initialize. occurs 1 times.
I occurs 5 times.
In occurs 2 times.
Now occurs 1 times.
Thanks. occurs 1 times.
a occurs 1 times.
a)". occurs 1 times.
a, occurs 1 times.
all occurs 2 times.
and occurs 1 times.
as occurs 1 times.
b)". occurs 1 times.
base occurs 1 times.
class occurs 1 times.
class, occurs 1 times.
codes occurs 1 times.
contained occurs 1 times.
copy occurs 1 times.
derived occurs 1 times.
do occurs 2 times.
funciton occurs 1 times.
function occurs 2 times.
have occurs 1 times.
in occurs 2 times.
include occurs 1 times.
int occurs 1 times.
just occurs 1 times.
more occurs 1 times.
need occurs 1 times.
operations occurs 1 times.
redefined occurs 1 times.
simple occurs 1 times.
that? occurs 1 times.
the occurs 6 times.
there occurs 1 times.
therefore occurs 1 times.
things, occurs 1 times.
to occurs 4 times.
want occurs 1 times.
ways occurs 1 times.
--------------------------------------------------------------------------------
-Mike

P.S. BTW if you want help, you should make it
easy for folks to help. With those line numbers
we can't paste and compile your code. It was
far easier for me to show you how I would do it
than to try to make your code compilable. (imo
your code is far more complicated than need be
anyway).

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