Re: what is wrong with this generic print function ?

From:

terminator <farid.mehrabi@gmail.com>

Newsgroups:

comp.lang.c++.moderated

Date:

Mon, 16 Feb 2009 16:22:33 CST

Message-ID:

<7454f113-7183-4344-b2b3-f767ca8da6e8@m15g2000vbl.googlegroups.com>

On Feb 16, 5:58 pm, shery.itt...@gmail.com wrote:

#include <iostream>
#include <vector>

using namespace std;

template<typename T>
void printvec(vector<T> var)
{
   for (vector<T>::iterator i=var.begin(); i!= var.end(); i++)
   {
     cout<<" value is "<<*i<<endl;
   }

}

int main()
{
   vector<int> vec;

   vec.push_back(10);
   vec.push_back(20);
   vec.push_back(30);
   vec.push_back(40);

   printvec(vec);

}

Read the last two error messages:

vector.cc:10: error: dependent-name ?std::vector::iterator? is parsed
as a non-type, but instantiation yields a type
vector.cc:10: note: say ?typename std::vector::iterator? if a type is
meant

since you are using a template nested type the above hints are to be
taken into consideration.
If the function 'printvec' hadn`t been templated this wouldn`t have
happened.

cheers,
FM.

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