Re: for_each problem

From:
Jerry Coffin <jcoffin@taeus.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 10 Apr 2009 12:58:54 -0600
Message-ID:
<MPG.244943202753e4979896e5@news.sunsite.dk>
In article <49df8801$1@news.cadence.com>, bowan2004@gmail.com says...

class A {
  void test(int k);
};

class Test {
  A* d_a;
  vector<int> d_array;

  void test() {
     typedef vector<int>::iterator VI;
     for (VI i=d_array.begin(); i != d_array.end(); ++i)
     {
         d_a ->test(*i);
     }
  }
};

Question:
How can I use for_each to replace this "for" loop in test()?


Minor nit: right now, A::test is private, so Test::test won't compile.
Most people find it all too easy to imitate that particular behavior,
but prefer not to do so. :-)

Less minor nit: right now, you've defined d_a as a pointer to an A, but
you have not initialized it to point at anything -- when you attempt to
dereference it, you get undefined behavior -- another of those things
people find it all too easy to do, but generally attempt to avoid.

for_each(d_array.begin(),
        d_array.end(),
        mem_fun(A::test)
);


First you have to make the member function public, of course. Then you
have to have an actual obect on which to invoke the member function, not
just a pointer to nowhere of the right type.

Then, if possible, you rename the member function from 'test' to
'operator()' -- that makes invoking it really easy, and at least as
you've posted it, with A having only one member function, you might as
well use that name:

std::for_each(d_array.begin(), d_array.end(), A());

I'll let somebody else deal with the ugliness that arises when you
insist on giving the member function a different name -- quite a while
ago, I decided that was a great deal of ugliness and work with
essentially no benefit. If you decide you want to do it anyway, there
are some additions to <functional> in TR1 and the upcoming revision to
the C++ standard that make it a bit easier than what's in C++ 03.

--
    Later,
    Jerry.

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