Re: vector representation
On Apr 9, 4:53 pm, "Paul" <pchris...@yahoo.co.uk> wrote:
If you want to convert to a vector of int , why do you return a string?
The conversion is only temporary and you do not see what its converted to=
,
what you need to do is something like this :
#include <iostream>
#include <string>
#include <vector>
template< template<typename T1, typename Alloc1> class C1, typename T1,
typename Alloc1,
template<typename T2, typename Alloc2> class C2, typename T2, typename
Alloc2>
void convert(const C1<T1, Alloc1>& vchar, C2<T2, Alloc2>& vint) {
for (std::size_t i=0; i<vchar.size(); ++i){
vint[i] = 0xF & static_cast<T2>(vchar[i]);
/*Mask the ascii value with 0xF to convert to int.*/
}
}
int main()
{
std::vector<char> vc(3);
vc[0]='1';
vc[1]='2';
vc[2]='3';
std::vector<int> vi(3);
convert(vc, vi);
for (int i=0;i<3; ++i ){
std::cout<< vi[i] <<'\t';
}
}
Thanks, but actually I don't need to convert (in this case I have
already conversions for other cases...).
I just want to use only one integer using 1 byte only, since I don't
need more.
So probably the solution of my problem could be simply to use this
typedef uint8_t hop_count_t;
and it might work already (even if now I get other errors, probably I
hardwired an int by mistake somewhere..)
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