Re: Will a const object be moved on return?

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 29 Sep 2011 16:40:23 -0700 (PDT)
Message-ID:
<j62tgi$qlo$1@dont-email.me>
Am 29.09.2011 20:02, schrieb Martin B.:

Isn't this something that could be improved in a future version of the
standard? C++ already considers a local l-value as an r-value on return,
wouldn't it make sense to "ignore" the constness? After all, the object
*is* gonna be destructed right away, and for it's dtor, the constness is
irrelevant (or so I like to think).


This is an interesting idea and looks doable. For copyable types like
strings this would be purely an optimization advantage (but a reasonable
one, don't get me wrong here). Even more interesting is that this would
also work for automatic and const, but move-only objects, e.g. when
using std::unique_ptr as in the following example:

std::unique_ptr<const X> source() {
  const std::unique_ptr<const X> p(...);
  ... // Work on p, but forbid *all* mutating operations.
  return p;
}

Greetings from Bremen,

Daniel Kr?gler

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