Re: Compile-time introspection of free-floating functions, does this work?

From:
Victor Bazarov <v.bazarov@comcast.invalid>
Newsgroups:
comp.lang.c++
Date:
Mon, 13 Feb 2012 14:21:44 -0500
Message-ID:
<jhbns9$emd$1@dont-email.me>
On 2/13/2012 2:11 PM, Juha Nieminen wrote:

   I think I might have come up with a way to detect at runtime if a
free-floating function has been defined or not, and avoid referencing
it if it isn't. More concretely, in a project of mine I need to know
if std::strtold exists in<cstdlib> or not, and call it only if it does
(and if it doesn't, fall back to calling std::strtod).

   What's the jury's opinion of this? Standard, non-standard, ill-formed,
suspicious? Any suggestions to make it better?

//---------------------------------------------------------------------
#include<iostream>
#include<cstdlib>

namespace std
{
     template<typename T1, typename T2>
     char strtold(T1, T2);
}

namespace
{
     const bool hasStrtold =
         (sizeof(std::strtold("0", (char**)0))> 1);

     template<bool> struct Func;

     template<> struct Func<false>
     {
         static void func() { std::cout<< "No strtold().\n"; }
     };

     template<> struct Func<true>
     {
         static void func()
         {
             std::cout<< "Has strtold(). Test:"
                       << std::strtold("12.3", (char**)0)<< "\n";
         }
     };

     void func()
     {
         Func<hasStrtold>::func();
     }
}

int main()
{
     func();
}
//---------------------------------------------------------------------


So far the only suspicious part in this code is when you define your own
'strtold' template in the 'std' namespace - are you allowed to? I am
not sure what the correct answer is to that.

Another small issue is that the Standard claims that 'strtold' exists.
Are you working to identify a non-compliance in a particular compiler?
I'm asking because a compliant compiler will have 'strtold' defined, I
think, at least according to 21.7/T78. Of course, I may have missed
something there...

V
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