Re: Compile-time introspection of free-floating functions, does this
work?
On 2/13/2012 2:11 PM, Juha Nieminen wrote:
I think I might have come up with a way to detect at runtime if a
free-floating function has been defined or not, and avoid referencing
it if it isn't. More concretely, in a project of mine I need to know
if std::strtold exists in<cstdlib> or not, and call it only if it does
(and if it doesn't, fall back to calling std::strtod).
What's the jury's opinion of this? Standard, non-standard, ill-formed,
suspicious? Any suggestions to make it better?
//---------------------------------------------------------------------
#include<iostream>
#include<cstdlib>
namespace std
{
template<typename T1, typename T2>
char strtold(T1, T2);
}
namespace
{
const bool hasStrtold =
(sizeof(std::strtold("0", (char**)0))> 1);
template<bool> struct Func;
template<> struct Func<false>
{
static void func() { std::cout<< "No strtold().\n"; }
};
template<> struct Func<true>
{
static void func()
{
std::cout<< "Has strtold(). Test:"
<< std::strtold("12.3", (char**)0)<< "\n";
}
};
void func()
{
Func<hasStrtold>::func();
}
}
int main()
{
func();
}
//---------------------------------------------------------------------
So far the only suspicious part in this code is when you define your own
'strtold' template in the 'std' namespace - are you allowed to? I am
not sure what the correct answer is to that.
Another small issue is that the Standard claims that 'strtold' exists.
Are you working to identify a non-compliance in a particular compiler?
I'm asking because a compliant compiler will have 'strtold' defined, I
think, at least according to 21.7/T78. Of course, I may have missed
something there...
V
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