Re: printing the union (help)

From:

red floyd <no.spam@here.dude>

Newsgroups:

comp.lang.c++

Date:

Tue, 13 Nov 2007 11:01:18 -0800

Message-ID:

<Pwm_i.9697$RR6.7224@newssvr22.news.prodigy.net>

Latina wrote:

Hi, I am doing a program of overloaded methods.
I want to get what is the union of the user set and S set and the user
set and S1 set.
I try it but it is not working.
Can some one help me please?

Define "Not working". What are you inputting? What are you getting
out? What are you expecting?

See FAQ 5.8 http://www.parashift.com/c++-faq-lite/how-to-post.html#faq-5.8

Post a minimal *COMPILABLE* example (see my comment below) that exhibits
the behavior in question. Tell us what you did, what you expected, and
what you got.

Here is part of my code:

class IntegerSet
{
private:
        bool set[26];
        int element;

public:
       //Operator methods.
       IntegerSet operator + (const IntegerSet &)const; //Method
union

};

This following method won't compile -- no prototype

void IntegerSet::setString()
{
    cout<<"{";
    for(element=0; element<26; element++)
    {
    if(set[element]==true)
           {
        cout<<" "<<element<<" ";
            }
     }
    cout<<"}";
}

Error. Implicit int not allowed.

main()
{
  for(int i=2; i<21; i++)
  {
          if(i%2==0)
              S1set.insertElement(i);
  }
  for(int z=0; z<26; z++)
  {
          Sset.insertElement(z);
  }

  int temp, ele;
  int newSet[26];

  cout<<"Enter how many elements you want in the set: ";
  cin>>ele;
  cout<<"Enter the values: \n";
  for(int i=0; i<ele; i++)
  {
       cout<<i+1<<": ";
       cin>>temp;
       newSet[i]=temp;
  }
  IntegerSet S4set(newSet, ele);
  cout<<"Your set is: ";
  S4set.setString();

  cout<<"\n\nSelect one of these choices:\n";
  cout<<" 1. Find Union \n";
  cout<<"Choice: ";
  cin>>choice;

  if(choice==1)
  {
      char a, b, option;

      cout<<"\nYour set is: ";
      S4set.setString();
      cout<<"\nSet S: ";
      Sset.setString();
      cout<<"\nSet S1: ";
      S1set.setString();

      cout<<"\n\nSelect one of this choices to find the union of:\n";
      cout<<" a. Your set and set 'S'\n";
      cout<<" b. Your set and set 'S1'\n";
      cout<<"Option: ";
      cin>>option;

      IntegerSet unio();

      if(option=='a'||option=='A')
      {

Why not: unio = S4set + Sset; ? That's the whole point of operator
overloading.

           unio = S4set.operator+(Sset);
      }
      else if(option=='b'||option=='B')
      {

See above.

           unio = S4set.operator+(S1set);
      }
      cout<<"The union of the two sets is: \n";
      unio.setString();
  }
}