Re: Does push_back() do a copy?

I have a socket class CTestClientSocket which I am using to simulate
load testing.

I create multiple instances of the client like this:

for (int i = 0; i < 5; i++)
{
    CTestClientSocket* pTemp = new CTestClientSocket(this, ip, port);
    pTemp->Connect();
    m_collClients.push_back(pTemp);
// delete pTemp;
}

Note I have commented out the delete pTemp

Then I send some data to a server like this:

// iterate through collection of clients
for (std::vector<CTestClientSocket*>::iterator it =
m_collClients.begin();
    it != m_collClients.end(); it++)
    {
        (*it)->Send(byData);
    }

This works if delete pTemp on the Connect is commented out. But I
thought that push_back would make a copy of pTemp.

and so I could
then delete pTemp. But if I delete pTemp I get an memory access
problem in the (*it)->Send(byData);

And I have to cleanup at the end. Does push_back NOT do a copy? I am
confused, can someone explain.

Or is there a better way to do this sort of thing?